-2=x^2-2x+2

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Solution for -2=x^2-2x+2 equation: 



-2=x^2-2x+2

We move all terms to the left:

-2-(x^2-2x+2)=0

We get rid of parentheses

-x^2+2x-2-2=0

We add all the numbers together, and all the variables

-1x^2+2x-4=0

a = -1; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·(-1)·(-4)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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